Answer:
5) y = 1x + 2
6) y = -0.5x + 6
Explanation:
5)
Given points are (-3, -1), (2, 4)
[tex]\sf slope \:formula: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]
Here, find slope:
[tex]\rightarrow \sf slope \ (a) = \dfrac{4-(-1)}{2-(-3)} = \dfrac{5}{5} = 1[/tex]
Find Equation:
y = ax + q
Here found that a = 1, take (x, y) = (-3, -1)
[tex]\sf -1 = 1(-3) + q[/tex]
[tex]\sf q - 3 = -1[/tex]
[tex]\sf q = -1 + 3[/tex]
[tex]\sf q = 2[/tex]
So, in total equation:
y = 1x + 2
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6)
Given points are (-2, 7), (2, 5)
[tex]\sf slope \:formula: \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]
Here, find slope:
[tex]\rightarrow \sf slope \ (a) = \dfrac{5-7}{2-(-2)} = -0.5[/tex]
Find Equation:
y = ax + q
Here found that a = -0.5, (x, y) = (-2, 7)
[tex]\sf 7 = -0.5(-2) + q[/tex]
[tex]\sf 7 = 1 + q[/tex]
[tex]\sf q = 7-1[/tex]
[tex]\sf q = 6[/tex]
So, in total equation:
y = -0.5x + 6
