The number of bacteria when t = 8 is approximately 66 bacterias
Given the function that gives the number of bacteria in a population as a function of time in hour expressed as:
P=48∙e^((0.045t))
If the value of t is 8, hence;
P=48∙e^((0.045(8))
P = 48e^0.36
P = 65.933
Hence the number of bacteria when t = 8 is approximately 66 bacterias
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