A bag contains 2 yellow balls, 3 green balls, 5 red balls and 6 black balls.
What is the probability of either a yellow ball or a red ball being drawn if
only one ball is drawn?

Respuesta :

Answer:

7/16

Step-by-step explanation:

(2+5)/(2+3+5+6) = 7/16

The probability of either a yellow or a red ball being drawn if only one is drawn is 7/16.

What is probability?

The probability is the measure of the likelihood of an event to happen. It measures the certainty of the event. The formula for probability is given by; P(E) = Number of Favourable Outcomes/Number of total outcomes.

According to the given question.

Numnber of yellow balls = 2

Number of green balls = 3

Number of red balls = 5

Number of black balls = 6

So,

The total number of balls in a bag = 2+ 3+ 5 + 6 = 16

And,

The sum of yellow and red ball = 2 + 5 = 7

Therefore,

The probability of either a yellow or a red ball being drawn if only one ball is drawn

= [tex]\frac{total\ number\ of \ red \ and \ yellow\ balls }{Total\ number\ of \ balls}[/tex]

[tex]= \frac{7}{16}[/tex]

Hence, the probability of either a yellow or a red ball being drawn if only one is drawn is 7/16.

Find out more inforation about probability here:

https://brainly.com/question/11234923

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