PLEASE HELP WILL GIVE YOU ALL MY POINTS In the picture, t || s, mz1 = 10x + 2, and mz2 = 12x - 22. Find the measure of angle 2.

Answer:
[tex]\huge\boxed{\sf < 2 = 122\°}[/tex]
Step-by-step explanation:
From the figure,
We know that:
So,
Add 22 to both sides
10x + 2 + 22 = 12x
10x + 24 = 12x
Subtract 10x to both sides
24 = 12x - 10x
24 = 2x
Divide 2 to both sides
12 = x
OR
Given that,
∠2 = 12x - 22
Put x = 12
∠2 = 12(12) - 22
∠2 = 144 - 22
[tex]\rule[225]{225}{2}[/tex]
Answer: 122°
Step-by-step explanation:
∠1 an ∠2 are alternate interior angles, which are angles that are inside both parentheses and are on alternate sides of the transversal. The Alternate Interior Angles Theorem states that if two lines are parallel and cut by a transversal, then the alternate interior angles formed are congruent.
Since the lines are parallel as given in the question, ∠1 and ∠2 are of equal measure. We can solve for ∠2 by first solving for x, then plugging it in ∠2's measure.
[tex]10x+2=12x-22[/tex]
[tex]-2x=-24[/tex]
[tex]x=12[/tex]
Putting x in the expression 12x-22, we get
[tex]12(12)-22\\144-22\\122[/tex]
Hence, the value of ∠2 is 122°.