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Did you ever purchase a bag of M&M Peanut candies and wonder about the distribution of
the colors? A recent article reported that 30 percent of the candies are brown, 20 percent yellow,
20 percent red, 20 percent green, and 10 percent orange. A one-pound bag of M&M peanut
candies was purchased at Wal-Mart here in Lubbock. A total of 188 candies were in the bag,
with 67 brown, 22 yellow, 51 red, 24 green, and 24 orange.
Fill in the following chart on the frequency of the colors.
Color Brown Yellow Red Orange Blue Green
Observed
Frequency
Expected
Frequency
Using the information from our sample bag, determine if our bag’s distribution matches the
advertised distribution. Use an alpha = 0.05.
1. What is the null hypothesis?
2. What is the alternative hypothesis?
3. What distribution are you using?
4. What test are you running?
5. What is the critical value?
6. What is your test value?
7. What is your conclusion?

Respuesta :

The null hypothesis is that the proportions are 0.30, 0.20, 0.20, 0.20, 0.10 and the alternative hypothesis is that the proportions are not as given above.

How to illustrate the information?

It should be noted that the null hypothesis is the theory that states that there is no statistical relationship between the variables.

In this case, the Chi square test can be run to get the desired information. Therefore, X² was gotten as 19.597. The degree of freedom is 4 and the p value is 0.0006 from the distribution table.

In this case, the critical value of 0.006 is less than the 0.05. Therefore, we need to reject the null hypothesis.

This implies that there's evidence that the distribution doesn't correlate with what we've.

Learn more about hypothesis on:

brainly.com/question/11555274

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