Answer:
[tex]x=-\frac{1}{2},\frac{5}{2}[/tex]
Step-by-step explanation:
1) Split the second term in [tex]4{x}^{2}-8x-5[/tex] into two terms.
1- Multiply the coefficient of the first term by the constant term.
[tex]4\times -5=-20[/tex] to -8 and multiply to -−20?
2 and −10
3 - Split -8x as the sum of 2x and -10x.
[tex]4x^2+2x-10x-5[/tex]
2) Factor out common terms in the first two terms, then in the last two terms.
[tex]2x(2x+1)-5(2x+1)=0[/tex]
3) Factor out the common term [tex]2x+1[/tex].
[tex](2x+1)(2x-5)=0[/tex]
4) Solve for [tex]x[/tex].
1 - Ask: When will (2x+1)(2x-5) equal zero?
When 2x + 1 = 0 or 2x - 5 = 0
2 - Solve each of the 2 equations above.
[tex]x=-\frac{1}{2},\frac{5}{2}[/tex]
