The vertex form of the equation is y = 3(x + 2)^2 - 5
The equation is given as:
y = 3x^2 + 12x + 7
Set to 0
3x^2 + 12x + 7 = 0
Subtract 7 from both sides
3x^2 + 12x = -7
Divide through by 3
x^2 + 4x = -7/3
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Take the coefficient of x
k = 4
Divide by 2
k/2 = 2
Square both sides
(k/2)^2 = 4
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So, we add 4 to both sides of x^2 + 4x = -7/3
x^2 + 4x + 4 = -7/3 + 4
Express as perfect square
(x + 2)^2 = -7/3 + 4
Multiply through by 3
3(x + 2)^2 = -7 + 12
Evaluate
3(x + 2)^2 = 5
Subtract 5 from both sides
3(x + 2)^2 - 5 = 0
Rewrite as
y = 3(x + 2)^2 - 5
Hence, the vertex form of the equation is y = 3(x + 2)^2 - 5
Read more about completing the square at:
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