The hydroxonium ion concentration of the fruit juice whose pH as given in the task content is; 5.6 can be evaluated as; [H3O+] = 2.51 × 10^-6.
Since the given pH of the fruit juice is 5.6, the hydroxonium ion concentration of the fruit juice can be evaluated by means of the formula as follows;
pH=-log[H3O+].
5.6 = -log[H3O+].
-5.6 = log[H3O+].
[H3O+] = antilogarithm (-5.6)
[H3O+] = 2.51 × 10^-6.
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