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A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is:
1712 the output is: 1712 is a leap year. Ex: If the input is: 1913 the output is: 1913 is not a leap year
Your program must define and call the following function. The function should return true if the input year is a leap year and false otherwise. def is_leap_year(user_year) Note: This is a lab from a previous chapter that now requires the use of a function,

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Based on the fact that the program should be able to return true if the input is a leap year, and false if the input is not, the program is shown below.

What program will return true if it is a leap year?

In order to make a program that tells whether a year is a leap year or not, you need to start off with the definition:

def is_leap_year(user year):

Then continuing the program, the full code would be:

def is_leap_year(user_year):

   if(user_year % 400 == 0):

       return True

   elif user_year % 100 == 0:

       return False

   elif user_year%4 == 0:

       return True

   else:

       return False

if __name__ == '__main__':

   user_year = int(input())

   if is_leap_year(user_year):

       print(user_year, "is a leap year.")

   else:

       print(user_year, "is not a leap year.")

If you input the year, 1712, the program would return the result, "1712 is a leap year."

Find out more on using programs to define functions at https://brainly.com/question/20476366

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