The angle between their paths to the nearest degree is 68⁰.
first displacement, a = 15 km/h x (45/60)
first displacement, a = 11.25 km
second displacement, b = 18 km/h x (45/60)
b = 13.5 km
c² = a² + b² - 2ab(cosθ)
2ab(cosθ) = a² + b² - c²
cosθ = (a² + b² - c²)/(2ab)
cosθ = (11.25² + 13.5² - 14²) / (2 x 11.25 x 13.5)
cosθ = 0.371
θ = arc cos(0.371)
θ = 68.22 ⁰
Thus, the angle between their paths to the nearest degree is 68⁰.
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