The equation of the asymptote is y = 3x - 5. The correct answer is option C
The distance from a point and the distance to a line in hyperbola is known as asymptote. The general equation is [tex]x^{2}/ a^{2} - y^{2}/b^{2} = 1[/tex]
From the given equation of hyperbola, which is
[tex]\frac{(x - 2)^{2}}{4}[/tex] - [tex]\frac{(y - 1)^{2} }{36}[/tex] = 1
The center (h , k) of the hyperbola = C(2, 1)
a = 2
b = 6
Where C = [tex]\sqrt{a^{2} + b^{2} }[/tex]
C = [tex]\sqrt{4 + 36}[/tex]
C = [tex]\sqrt{40}[/tex]
C = [tex]2\sqrt{10}[/tex]
The equation of the asymptote will be y - K = +/-(b/a)(x - h)
That is,
y - 1 = +/-(6/2)(x - 2)
y - 1 = +/-3(x - 2)
y - 1 = +/-3x - 6
y = +/-3x - 6 + 1
y = +/- 3x - 5
Therefore, the equation of the asymptote is y = 3x - 5.
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