Respuesta :

Here
X1=-1, y1=4
X2=1, y2=-1

We have d=under root (x2-x1)sq+y2-y1)sq
=(1-(-1)sq + (-1-4)
=2sq+-5sq
=4+25
=29ans
Sprnt

Answer:

D(distance)= [tex]\sqrt{29}[/tex] or 5.3852, approximately.

Step-by-step explanation:

Distance formula: [tex]d=\sqrt{(x_{2} -x_{1} )^{2}+(y_{2} -y_{1} )^{2} } .[/tex]

1. Name the variables.

Let -1 be [tex]x_{1}[/tex]. Therefore, 4 will be [tex]y_{1}[/tex].

Let 1 be [tex]x_{2}[/tex]. Therefore, -1 will be [tex]y_{2}[/tex].

2. Substitute the values in the formula and calculate.

[tex]d=\sqrt{((1) -(-1) )^{2}+((-1) -(4) )^{2} } \\ \\d=\sqrt{(1+1 )^{2}+(-1-4 )^{2} }\\ \\d=\sqrt{(2 )^{2}+(-5 )^{2} }\\ \\d=\sqrt{4+25 }\\ \\d=\sqrt{29}[/tex]

3. Express the result.

D(distance)= [tex]\sqrt{29}[/tex] or 5.3852, approximately.