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Part 1) The only swimming pool at the El Cheapo Motel is outdoors. It is 5.0 m wide and 12.0 m long. If the weekly evaporation is 2.35 in., how many gallons of water must be added to the pool if it does not rain?

Part 2) If during the next week the pool still loses 2.35 in. of water to evaporation, even with 29 mm of rainfall, how many liters of water must be added?

Respuesta :

adioabiola

The gallons of water that must be added to the pool if it does not rain is 946.10 gallons

Volume of the pool

  • Width = 5.0 m
  • Length = 12.0 m
  • Weekly evaporation = 2.35 in

Convert meter to inches

1 m = 0.393701 inch

12.0 m = 472.44 inch

5.0 m = 196.85 inch

Volume of water evaporated weekly = length × width × 2.35 inch

= 472.44 inch × 196.85 inch × 2.35 inch

= 218,550.12 cubic inches

Convert cubic inches to gallons

1 gallon = 231 cubic inches

Volume of water evaporated weekly = 218,550.12 cubic inches / 231 cubic inches

= 946.10 gallons

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