A square and a rectangle have diagonals of 52 cm. The rectangle has a side of 20 cm. Which polygon has the largest area? Which polygon has greater perimeter? Explain.

Respuesta :

The polygon with greater area is the square and that with greater perimeter is the rectangle, this is so because the length of sides of the square differ from that of the rectangle

How to determine the parameters

From the information given, we have that:

  • Diagonal of rectangle and square is 52cm
  • Side of the rectangle is 20cm

Formula for perimeter of a rectangle

Perimeter = [tex]2l + 2 \sqrt{d^2 - l^2}[/tex]

Perimeter = 2( 20) + 2 [tex]\sqrt{52^2 - 20^2}[/tex]

Perimeter = 40 + 2 ( 48)

Perimeter = 136 cm

Perimeter of a square = 2 √2d

Perimeter = 2 √ 2(52)

Perimeter = 2√104

Perimeter = 20. 3 cm

Area of square = 1/2 diagonal square

Area = 1/ 2 × 52²

Area = 1352 cm²

Area of rectangle = [tex]l\sqrt{d^2 - l^2}[/tex]

Area = 20 [tex]\sqrt{52^2 - 20^2}[/tex]

Area = 20 × 48

Area = 960cm²

Thus, the polygon with greater area is the square and that with greater perimeter is the rectangle, this is so because the length of sides of the square differ from that of the rectangle

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