Respuesta :
A shuffleboard disk is accelerated at a constant rate from rest to a speed of 6.0 m/s over a 1.8 m distance by a player using a cue. at this point the disk loses contact with the cue and slows at a constant rate of 2.5 m/s2until it stops. Therefore, it takes about 3 seconds to elapse from, when the disk begins to accelerate until it stops. It is because,
Given, u = 0 m/s, v = 6 m/s and s = 1.8 m
It is given that acceleration is constant so we can use,
⇒ v² = u² + 2as
Hence, putting the values, u = 0 m/s, v = 6 m/s and s = 1.8 m,
⇒ (6)² = 0² + 2 a × 1.8
⇒ a = 10 m/s²,
Using v = u + at,
Putting values again, u = 0 m/s, v = 6 m/s and a = 10 m/s²,
⇒ 6 = 0 + 10t
⇒ t = 0.6 s
Time taken during distance 1.8 m in 0.6 seconds,
Now, acceleration changes as, a = -2.5 m/s² and board stops, that is v =0,
⇒ v = u + at,
Putting values, u = 6 m/s, v = 0 m/s and a = -2.5 m/s²
⇒ 0 = 6 - 2.5t,
⇒ t = 2.4 s,
Time taken during to stop after 1.8 m is 2.4 seconds.
Total time taken = 2.4 + 0.6 = 3 seconds.
To learn more about acceleration here
brainly.com/question/12550364
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