How do you do number 61?

The remainder of the synthetic division is 0, hence x + 2 is a factor of the polynomial
For an expression to be a factor of a polynomial, hence the remainder of the polynomial must be zero
Given the polynomial function x^3-2x^2-5x+6 divided by x + 2 according to the synthetic division
x^2 - 4x + 3
x + 2 | x^3-2x^2-5x+6
x^3 + 2x^2
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-4x^2 - 5x
-4x^2 - 8x
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3x + 6
3x + 6
Since the remainder of the synthetic division is 0, hence x + 2 is a factor of the polynomial
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