contestada

find the mass of water that has a specific heat of 4.18 J/g C that requires 1500 J of energy to go from 33C to 113 C

Respuesta :

Answer:

4.49 g

Explanation:

To find the mass of water, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

You can plug the given values into the equation and solve for "m".

Q = 1,500 J                       c = 4.18 J/g°C

m = ? g                              ΔT = 113°C - 33°C = 80°C

Q = mcΔT                                                   <----- Specific Heat Equation

1,500 J = m(4.18 J/g°C)(80°C)                    <----- Insert values

1,500 J = m(334.4)                                      <----- Multiply 4.18 and 80

4.49 = m                                                     <----- Divide both sides by 334.4