Write an equation of the line in general form through the following point and that is perpendicular to the given
line below.
(-2/3 , 7/9)
3x+4y=7

Respuesta :

The point slope equation is y = (-3/4) x +5/18.

According to the statement

we have find that the equation of the line in general form.

So, For this purpose, we know that the

The point slope form of a linear equation is (y - y1) = m(x - x1) and is useful for finding the equation for a line when you know one point along the line and the slope of the line.

And from the given information:

Two lines are perpendicular And the given equation is

3x+4y=7

And from this the slope becomes

4y = -3x +7

y= -3/4x +7/4

So, the slope becomes -3/4.

And the given points are the (-2/3 , 7/9)

Now, take the equation Using point slop formula, you can derive the equation of the line as following:

y - 7/9 = -3/4 (x+2/3)

which is y = (-3/4) x - 1/2+7/9

y = (-3/4) x - 1/2+7/9

y = (-3/4) x - 9+14/18

y = (-3/4) x +5/18.

So, The point slope equation is y = (-3/4) x +5/18.

Learn more about point slope form here

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