Find the coordinates of a point P on the line and a vector v parallel to the line.

[tex]\frac{x-2}{3} = \frac{y+1}{9} = z+8[/tex]

P(x,y,z)=(___)
V=__

Respuesta :

The point (2, -1 , -8) is on the line and the expression (3, 9, 1) represents the family of vectors parallel to the line.

How to find a point on a line and a vector parallel to the line

First, we have to find the vector expression of the line function based on the following parametric equations:

t = (x - 2) / 3          (1)

x = 3 · t + 2

t = (y + 1) / 9          (2)

y = 9 · t - 1

t = z + 8                 (3)

z = t - 8

(x, y, z) = (2, - 1, - 8) + t · (3, 9, 1)        (4)

The point (2, -1 , -8) is on the line and the expression (3, 9, 1) represents the family of vectors parallel to the line.

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