Zeolite A, [(AlO₂)₁₂(SiO₂)₁₂] .27 H₂O, is used to soften water by replacing Ca²⁺ and Mg²⁺ with Na⁺. Hard water from a certain source is 4.5 × 10⁻³MCa²⁺ and 9.2 × 10⁻⁴MMg²⁺, and a pipe delivers 25,000 L of this hard water per day. What mass (in kg) of zeolite A is needed to soften a week’s supply of the water? (Assume zeolite A loses its capacity to exchange ions when 85 mol % of its Na1 has been lost.)

Zeolites are 3-dimensional crystalline solids which are formed either synthesized or can be naturally. Zeolites belongs to class microporous solids.

Given

Hard water supply per day = 25,000L

Ca⁺² concentration = 0.0045 mol/L

Total mole of Ca⁺² = 25,000 × 0.0045

= 112.5 mol

Mass of Ca⁺² in hard water = Mole × Molar mass

= 112.5 × 40.08 g

= 4509 g

Concentration of Mg⁺² = 0.00092 mol/L

Total mole of Mg⁺² = 0.00092 × 25000

= 23

Mass of Mg⁺² in Hard water = Mole × Molar mass

= 23 g × 18.04

= 414.92 g

Molar mass of Zeolite = 2190g/mol

No of mole of Ca⁺² removed by 1 mole of Zeolite A = 6

Mass of Ca⁺² removed by 2190 g of Zeolite A = 240.48g

Mass of Zeolite A required to remove 4509 g of Ca⁺² = 33.73kg

Assume efficiency of Zeolite is 85%

To remove Ca⁺² the mass of Zeolite A = 39.68kg

No of mole of Mg⁺² removed by 1 mole of Zeolite A = 6

Mass of Mg⁺² removed by 2190g of Zeolite A = 145.86g

To remove 414.92 g of Mg⁺² the mass of Zeolite = 6.59kg

Assume the 85% as the efficient of Zeolite A

Mass of Zeolite A required to remove Mg⁺² = 7.75kg

Total mass of Zeolite A = 39.68kg + 7.75kg

= 47.43kg

Thus from the above conclusion we can say that 47.43 kg of Zeolite A is needed to soften a week's supply of the water.

Learn more about the Zeolites here: https://brainly.com/question/14976531

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