Bismuth(V) compounds are such powerful oxidizing agents that they have not been prepared in pure form. How is this fact consistent with the location of Bi in the periodic table?

Respuesta :

Bismuth(V) cannot be prepared from the pure form because Bi(III) is more stable. Bi(V)+2e−→Bi(III)

The periodic table's group 5A includes bismuth. It is also from period 6. Group 5A elements often exist in oxidation states 33 and 55. However, the only possible oxidation number for bismuth is +3. The chemical element bismuth has the atomic number 83 and the symbol Bi. It is a radioactive post-transition metal and one of the pnictogens, with chemical characteristics similar to those of its lighter group 15 siblings, antimony and arsenic.

This is due to its historical location. Due to the inert-pair effect, it is typical for elements in periods 6 and 7 to have lower oxidation states that are more stable than higher oxidation states. Because bismuth(V) cannot exist in its pure state, it can readily accept two electrons. It is easily convertible back into bismuth(III), making it a potent oxidizing agent.

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