Enthalpy of reaction for (H + H + H⁺ → H₃⁺) is -769kJ/mol.
Since,
we have to calculate the heat of reaction for:
H + H + H⁺ → H₃⁺
Now,
The triatomic molecular ion H₃⁺ was first detected and characterized by J. J. Thomson using mass spectrometry.
Now,
Bond energy of H₂ = -432 kJ/mol
Proton affinity of H₂ (H₂ + H⁺→ H₃⁺) ΔH = –337 kJ/mol
Hence,
we have to apply Hess’s law to find out the heat of reaction. The bond energy of H₂ is exothermic because heat is given off when the two H-atoms combine to form H₂.
hence,
The equations can be written as,
H + H → H₂ BE = -432 kJ/mol
H₂ + H⁺ → H₃⁺ = -337 kJ/mol
Now,
H + H + H⁺ → H₃⁺ = -769 kJ/mol
Thus form the above conclusion we can say that the heat of reaction for the overall reaction is found to be -769 kJ/mol.
Learn more about Hess's Law here:https://brainly.com/question/16795968
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