Respuesta :

For a reaction at a given T,the rate increases by decrease in Ea .

The relation between rate constant and activation energy ( which is denoted by Ea ) is given as ,

K = A [tex]e^{-Ea/RT}[/tex]

K = A / [tex]e^{Ea/RT}[/tex]

On increasing value of Ea that is activation energy the value of [tex]e^{Ea/RT}[/tex] is increases . Hence , value of rate constant decreases because rate constant is inversely proportional to the  [tex]e^{Ea/RT}[/tex] . Since rate constant is directly proportional to the rate of the reaction .

Therefore , overall we can say that the rate is increases on decreasing Ea or activation energy .

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