Human liver enzymes catalyze the degradation of ingested toxins. By what factor is the rate of a detoxification changed if an enzyme lowers the Ea by 5 kJ/mol at 37°C?

Respuesta :

Simply put, activation energy is the minimal amount of energy required to activate a molecule, which causes the molecule to engage in physical movement. It is often referred to as the minimal amount necessary to start a chemical reaction. The use of a catalyst makes it simple to lower the activation energy.

Given,

The difference in the activation energy ΔEₐ = 5KJ/mol = 5X1000 J/mol

The value of total temperature is T = 37°C = (37+273)k = 310k

The mathematical expression of the Arrhenius equation is shown below,

k = Ae - Ea/RT

ln (k) = ln(A) - Ea/RT   .........(1)

Here,

Ea = the activation energy,

A = the frequency factor,

R = the universal gas constant, and

T = the temperature

Write eq(1) for first rate constant k₁

ln(k₁) = ln(A) - Ea/RT  ...........(2)

Here k₁ is first rate constant and Ea is first activation energy

write equation (1) for second rate constant k₂

ln(k₂) = ln(A) - Ea₂/RT   ...........(3)

Here k₂ is first rate constant and Ea₂ is first activation energy

Subtract eq(3) by (2)

ln(k₂) - ln(k₁) = (ln(A)- Ea₂/RT) - ln(A) + Ea/RT

ln (k₂/k₁) = (Ea/RT) - (Ea₂/RT)

ln (k₂/k₁) = (Ea - Ea₂)/RT

ln (k₂/k₁) = ΔEₐ/RT ................(4)

Value of universal gas constant (R) = 8.314 J/mol K

ln (k₂/k₁) = (5 X 1000 J.mol)/(8.314 J/mol K) (310 K)

ln (k₂/k₁)  = 1.94

(k₂/k₁) = [tex]e^{1.94}[/tex]

(k₂/k₁) = 6.96

Therefore, the factor by which the rate of detoxification changes is 6.96

Learn more about the Activation energy with the help of the given link:

https://brainly.com/question/11334504

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