The empirical formula of 0.063 mol of chlorine atoms combined with 0.22 mol of oxygen atoms is Cl₂O₇
The empirical formula of a chemical compound in chemistry is the simplest whole number ratio of atoms in a compound. Two simple instances of this concept are the empirical formulas of sulfur monoxide (SO) and disulfur dioxide (S2O2). As a result, the empirical formulas for the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide are the same.
The preliminary formula for the compound is Cl₀.₀₆₃O₀.₂₂. Divide all the subscripts by the subscript with the smallest value which is 0.063.
Cl[tex]\frac{0.063}{0.063}[/tex]O[tex]\frac{0.22}{0.063}[/tex] → Cl₁.₀₀O₃.₄₉ ≈ Cl₁O₃.₅
Multiply all the subscripts by 2 to turn all the subscripts into integers. The empirical formula is Cl₂ O₇.
To learn more about empirical formula visit:
https://brainly.com/question/14044066
#SPJ4
