Respuesta :
The enthalpy of formation of CF[tex]4[/tex] is -678.82 kJ/mol.
What is enthalpy ?
The equation for the enthalpy change of the above reaction is:
Δ[tex]H_{}[/tex] [tex]rxn[/tex] = [ (4× Δ[tex]H_{f}[/tex] [tex]HF[/tex]) + (2× Δ[tex]H_{f}[/tex] [tex]Cf_{4}[/tex]) - (1× Δ[tex]H_{f}[/tex] [tex]C_{2}H_{4}[/tex] ) + ( 6×Δ[tex]H_{f}[/tex] [tex]f_{2}[/tex] )]
We are given:
Δ[tex]H_{f}[/tex] [tex]C_{2}H_{4}[/tex] = 52.26 KJ/mol
Δ[tex]H_{f}[/tex] [tex]HF[/tex] = -271.1 KJ/mol
Δ[tex]H_{f}[/tex] [tex]f_{2}[/tex] = 0 KJ/mol
Δ[tex]H_{}[/tex] [tex]rxn[/tex] = -2496.7KJ/mol
Therefore enthalpy is -678.82 kJ/mol.
A thermodynamic system's enthalpy H is calculated by multiplying its internal energy by the product of its pressure and volume. In the equation H = U + pV, U stands for internal energy, p for pressure, and V for system volume; pV is also frequently referred to as the pressure energy P.
The amount of heat in a system under constant pressure is measured as enthalpy (H). Chemists frequently gauge how the enthalpy of chemical systems changes when reactants transform into products. The enthalpy change, which is the same thing as the heat that is absorbed or released by a process at constant pressure, is denoted by the letter H.
To learn more about enthalpy from the given link:
brainly.com/question/3393755
#SPJ4
