Concentration of [tex]CO[/tex] = 0.328 M
Concentration of [tex]Cl_{2}[/tex] = 0.328 M
Concentration of[tex]COCl_{2}[/tex] = 0.532 M
Chemical equilibrium refers to the situation in a chemical process where both the reactants and products are present in concentrations that have no further tendency to vary over time, preventing any discernible change in the system's characteristics.
Moles of [tex]CO[/tex] and [tex]Cl_{2}[/tex] = 0.430 mole
Volume of solution = 0.500 L
Initial concentration of [tex]CO[/tex] and [tex]Cl_{2}[/tex] = 0.860
The given balanced equilibrium reaction is,
CO(g) + Cl₂(g) ⇄ COCl₂(g)
Initial conc. 0.860M 0.860M 0
At eqm. conc. (0.860-x) M (0.860-x) M (x) M
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.532 M
Thus, the concentrations of at equilibrium are :
Concentration of [tex]CO[/tex]= (0.860-x) M =(0.860-0.532) M = 0.328 M
Concentration of[tex]Cl_{2}[/tex] = (0.860-x) M = (0.860-0.532) M = 0.328 M
Concentration of [tex]COCl_{2}[/tex]= x M = 0.532 M
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