Mass of isobutylene = 0.847 g
Mass of CO2 = 2.656 g
Mass of H2O = 1.089 g
1st we have to calculate the mass of C and H as follows,
Mass of C [tex]= 2.657[/tex] × [tex]\frac{12.01}{44.01}[/tex]
[tex]= 0.275 g[/tex]
Mole of C atoms = 0.725g/ 12 g mol-1 = 0.06 mol
Mass of H = 1.089 × [tex]\frac{2.016}{18.02}[/tex]
= 0.122 gm
Mole of H = 0.122g / 1.008 g mol-1
= 0.12 mol
If we will combine both then, [tex]C_{0.06}H_{0.12}[/tex]
Now divide Both the values (moles) by 0.06 = [tex]C_{0.06/0.06}H_{0.12/0.06}[/tex]
= [tex]CH_2[/tex]
Thus the empirical formula isobutylene is found to be [tex]CH_2[/tex]
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