Respuesta :
Hypochlorous acid, HClO, has a pKa of 7.54, in 0.115 M [HCLO] [H₃O⁺] = 5.75 × 10⁻⁵, pH = 4.24, [ClO⁻] = 5.75 × 10⁻⁵ and [HCLO] = 0.015 M
What is hypochlorous acid?
When chlorine dissolves in water, hypochlorous acid (HClO, HOCl, or ClHO) is produced. Hypochlorous acid then partially dissociates to produce hypochlorite, ClO. Oxidizers and the main disinfectants in chlorine solutions are HClO and ClO. Since HClO quickly equilibrates with its precursor, chlorine, it is impossible to separate HClO from these solutions.
Many commercial bleaches, deodorants, and disinfectants contain the related substances sodium hypochlorite (NaClO) and calcium hypochlorite (Ca(ClO)2) due to their potent antibacterial characteristics. Hypochlorous acid is also present in the white blood cells of mammals, including humans, as a defence mechanism against foreign objects.
We have given that pKa = 7.54 and [HCLO] = 0.115 M
Lets find Ka
pKa = -log(Ka)
Ka = [tex]10^{-pKa}[/tex]
= [tex]10^{-7.54}[/tex]
= 2.88 × 10⁻⁸
Lets now make the ICE table to get eq. for Ka
[HCLO] + H₂O ⇆ H₃O [C]
I 0 0 0
C -x +x +x
E 0.115 M-x +x +x
Now, we know that H₃O = x = [ClO⁻] =
Ka = [tex]\frac{[H_3O^+][ClO^-]}{[HCLO] }[/tex]
= [tex]\frac{x^2}{0.115-x}[/tex]
= [tex]\frac{x^2}{0.115}[/tex]
x² = (Ka)(0.115)
x = [tex]\sqrt{(Ka)(0.115)}[/tex]
x = [tex]\sqrt{(2.88*10^{-8})(0.115)}[/tex]
= 5.75 × 10⁻⁵
As x = H₃O = [ClO⁻] , therefore H₃O = [ClO⁻] = 5.75 × 10⁻⁵
Lets find pH
pH = log(H₃O)
= log(5.75 × 10⁻⁵)
= 4.244
Learn more about Hypochlorous acid
https://brainly.com/question/11049140
#SPJ4
