In a combination reaction, 1.62 g of lithium is mixed with 6.50 g of oxygen.
(c) After reaction, how many grams of each reactant and product are present?

Respuesta :

After reaction, 4.63 g of O2 and 0 g of Li are still present. 3.487 g of Li2O were also produced by the process.

Steps

Equation

4Li (s) + O2 (g)-->2Li2O

moles of oxygen needed= (0.2334 mol Li)( 1 mol O2 / 4mol Li)

moles of oxygen needed=0.0584 mol O2

moles of oxygen in excess= (moles of O2 ) - (moles of oxygen needed)

moles of oxygen in excess=0.2031 mol O2 - 0.0584 mol O2

moles of oxygen in excess= 0.1447 mol O2

at the end

moles of oxygen = (0.1447 mol O2) ( 32g of O2/ 1 mol O2)

mass of oxygen=4.63g O2

moles of Li= 0 mol

mass of Li= 0g

mass of Li2O=(0.1167 mol Li2O ) ( 29.882 g Li2O /1 mol Li2O  )

mass of Li2O=3.487 g  Li2O

After reaction, 4.63 g of O2 and 0 g of Li are still present. 3.487 g of Li2O were also produced by the process.

What is an example of a combination reaction?

Combination reactions occur when two or more reactants come together to create a new product. Synthesis reaction is another name for combination reaction. For instance, hydrogen and chlorine can be joined to form hydro-chloride.

H + Cl -----> HCl (acid)

learn more about combination reaction here

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