the average power output of the sun is 3.8 × [tex]10^{26}[/tex] W given that about 1350 w/m2 reaches the upper atmosphere of the earth.
As we know intensity falling over a surface is equal to Energy falling per unit area per unit volume.
I = [tex]\frac{Energy}{area*time}[/tex]
Since Power is equal to energy/time
I = power/area
or
Power = Intensity × area
Now, Distance from Sun to Earth , r = 149.6 ×[tex]10^{9}[/tex] m
So, Surface area of the sphere of radius is:
A = 4 π [tex]r^{2}[/tex]
= 4 × 3.14 × (149.6 × [tex]10^{9}[/tex])²
= 2.81 × [tex]10^{23}[/tex]m²
Thus Average Power output of the sun will be:
P = 1350 × 2.81 × [tex]10^{23}[/tex]
= 3.7935 × [tex]10^{26}[/tex]
P = 3.8 × [tex]10^{26}[/tex] W
So the average power output of the sun is 3.8 × [tex]10^{26}[/tex] W.
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Answer:
Average power output of sun will be 3.8x10^26 W
Explanation:
As
Power= energy/time eq(1)
And, Intensity= energy/area x time eq(2)
From eq(1) & eq(2), we get
Intensity= Power/Area
So Power =intensity x area
And area is 4 π r^2 i.e= surface area of sphere and radius of earth=r = 149.6 × 10^9 m
A= 4x3.14x(149.6x10^9)2
A= 2.81x10^23 m2
And Power will be
P=1350x2.81x10^23
So we will get
P=3.8x10^26 W
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