The value of standard entropy of the reaction is -172.34j/mol. K .
Therefore , the sign is negative .
Given ,
The balanced chemical equation is , 3NO(g) → N2O (g) + NO2 (g)
We know ,
The standard entropy of the molecules as ,
S°(NO) = 210.8j/mol. K
S°(N2O) = 219.96 j/mol. K
S°(NO2) = 240.1 j/mol. K
The standard entropy of the reaction is given by ,
ΔS°rxn = sum of the S°(product) - sum of the S°(reactants )
= [219.96 j/mol. K + 240.1 j/mol. K ] - [ 3×210.8j/mol. K]
= 460.06j/mol. K - 632.4j/mol. K
= - 172.34 j/mol. K
Hence , the value of standard entropy of the reaction is -172.34j/mol. K .
Therefore , the sign is negative .
A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .
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