Consider the combustion of butane gas:C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g) (a) Predict the signs of ΔS° and ΔH°. Explain.

Respuesta :

The signs of ΔS° and ΔH° will be negative.

A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.

Combustion reactions must involve O2 as one reactant.

Consider the combustion of butane gas:

C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g)

4             + 13/2               4         +   5

10.5 mol -------------> 9 mol

As the number of moles decreases entropy will decrease

so ΔS° = negative

since this example for combustion reaction heat is released (exothermic)

so  ΔH° = negative.

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