A 75.0-g sample of dinitrogen monoxide is confined in a 3.1-L vessel then its pressure (in atm) at 115°C is 18.67 atm.
Calculation ,
According to ideal gas equation ,
PV = nRT
Where P is the pressure of sample of dinitrogen monoxide = ?
V is the volume confined by sample of dinitrogen monoxide = 3.1 L
n is the number of moles of sample of dinitrogen monoxide = given mass/molar mass
number of moles of sample of dinitrogen monoxide ( n ) = 75 g / 44 g/mol = 1.82 mol
R is the universal gas constant = 0.082 L.atm/K.mol
T is the temperature = 115°C = 115 + 273 = 388 K
Putting the value of V , n ,R and T in equation ( i ) we get the Pressure of sample of dinitrogen monoxide .
P×V = 1.82 mol×0.082 L.atm/K.mol× 388 K
P = 1.82 mol×0.082 L.atm/K.mol× 388 K / 3.1 L = 18.67 atm
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