contestada

Combustible vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a combustible mixture is called the lower flammable limit (LFL). Generally, the LFL is about half the stoichiometric mixture, the concentration required for complete combustion of the vapor in air.
(a) If oxygen is 20.9 vol % of air, estimate the LFL for n-hexane, C₆H₁₄.

Respuesta :

If oxygen is 20.9 vol % of air then LFL for n-hexane  [tex]C_{6} H_{14} .[/tex]is 1.1percent LFL is half the stochiometric amount so LFL is 1.1 percent.

When carbon reacts with hydrogen and oxygen then it will form carbon di-oxide and water.

[tex]2C_{6} +H_{14} +19O_{2}[/tex] ⟶[tex]12CO_{2} +14H_{2} O[/tex]

Concentration needed for complete combustion is calculated through the ratio of our compound and oxygen. To make it easier, let`s imagine we have 100 moles of air. That means we have 20.9 moles of [tex]O_{2}[/tex]

Stochiometric amount of hexane needed to react with that amount of  [tex]O_{2}[/tex] would be 20.9 *2 /19=2.2 mol .

If oxygen is 20.9 vol % of air then LFL for n-hexane [tex]C_{6} H_{14} .[/tex]is 1.1percent

LFL is half the stochiometric amount so LFL is 1.1 percent.

To know more about the Stochiometric here

https://brainly.com/question/12912444

#SPJ4

Otras preguntas