At cathode
Mn^+2 + 2e- → Mn (reduction)
At anode
Fe → Fe^+2 + 2e- (oxidation)
Mn^+2 + Fe → Mn + Fe
1) Identify the reducing and oxidizing agents. To do this, we must determine their oxidation numbers.2) For oxidation and reduction, write half-reactions. To equalize the charges on both sides, we use electrons. Get the redox reaction, third. (1) and (2) can be combined to produce the redox reaction. The balanced redox reaction shouldn't have any electrons from the half-reactions.
One species is reduced and another is oxidized in redox reactions. As a result, the species in question must shift in oxidation state. These reactions play a crucial role in the production and usage of energy in a variety of living systems, including humans and energy storage devices (batteries).
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