The redox reaction is
Ni²⁺(aq) + Pb(s) → Ni(s) + Pb²⁺(aq)
The given reaction is spontaneous and E°cell value is 0.39V.
The reaction in which both the reduction as well as oxidation reaction takes place at the same time in the chemical reaction is known as redox reaction.
Oxidation reactions are those kind of reaction in which compound, substance looses its electrons. In this type of reaction, oxidation state of an element goes on increasing.
Reduction reactions are those kind of reaction in which compound or substance or compound accept the electrons. In this type of reaction, oxidation state of an element goes on decreases.
The two-half reactions are as follow:
At cathode
Ni²⁺(aq) + 2e- → Ni(s) E° (Ni) = 0.26V
At anode
Pb(s) → Pb²⁺(aq) + 2e- E°(Pb) = -0. 13V
Redox reaction:
Ni²⁺(aq) + Pb(s) → Ni(s) + Pb²⁺(aq)
According to the voltaic cell, the half-cell reaction (2) is oxidation reaction therefore, it occurs at anode and the half-cell reaction (1) is reduction reaction therefore, it occurs at cathode.
E°cell = E°(Ni) - E°(Pb)
= 0.26 -(-0.13)
= 0.39V
Thus, we concluded that the balanced redox reaction is
Ni²⁺(aq) + Pb(s) → Ni(s) + Pb²⁺(aq) and E°cell value is 0.39V.
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