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Write a balanced half-reaction for the product that forms at each electrode in the aqueous electrolysis of the following salts:(a) LiF;

Respuesta :

Balanced Half reactions are:

Now at Anode reaction will occur as given:

2 [tex]F^-[/tex] ==> F₂+ 2[tex]e^-[/tex] + H₂O ==> [tex]FO^-[/tex]+ 2[tex]H^+[/tex] + [tex]F^-[/tex]  

At Cathode:

2  [tex]H^+[/tex]+  2[tex]e^-[/tex] ==> H₂

Since the question states that you are using an aqueous solution of LiF,  so water and LiF both are present and both dissociate in ion as

LiF-----------> [tex]Li^+ + F^-[/tex]

[tex]H_2O[/tex]--------------> [tex]H^+ +OH^-[/tex]

Now at Anode reaction will occur as given:

2 [tex]F^-[/tex] ==> F₂+ 2[tex]e^-[/tex] + H₂O ==> [tex]FO^-[/tex]+ 2[tex]H^+[/tex] + [tex]F^-[/tex]  (will occur)

At Cathode:

2  [tex]H^+[/tex]+  2[tex]e^-[/tex] ==> H₂ (will occur)

At Cathode:

[tex]Li ^+[/tex]  +  [tex]e^-[/tex]   ==> Li(This reaction will not occur)

The deposition of solid Li will not occur because in aqueous solution,  [tex]H^+[/tex]will be reduced before   [tex]Li ^+[/tex] .

The reduction potentials for  [tex]H^+[/tex] is zero whereas reduction potential for    [tex]Li ^+[/tex]is -3.04 V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

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