The cell is operating at the efficiency of 77.7%
Efficiency = [tex]\frac{\text{mass of Cu deposited}}{W} \times 100\%[/tex]
where,
W = mass of Cu that should have been deposited if the electrolytic cell.
Calculation of W:
[tex]W = \frac{Z \times i \times t}{96486}[/tex] ....(ii)
Here,
Z = equivalent mass of Cu
since, Cu⁺² + 2e⁻ → Cu
so, change of 2 electrons is taking place, n factor = 2
Equivalent mass of Cu (Z) = [tex]\frac{\text{mass}}{2}[/tex]
= [tex]\frac{63.5}{2}[/tex]
Given,
i = current = 5.8 A
t = time = 10 h = (10 × 60 × 60) sec
1 Faraday = 95486 C
Now, putting all the value in equation (ii) , we get
[tex]W = \frac{Z \times i \times t}{96486}[/tex]
W = 63.5 × 5.8 × 10 × 60 × 60
2 × 96486
W = 68.7
Therefore, from equation (i)
Efficiency = [tex]\frac{\text{mass of Cu deposited}}{W} \times 100\%[/tex]
= [tex]\frac{53.4}{68.7} \times 100\%[/tex]
= 77.7 %
Thus from the above conclusion we can say that the cell is operating at an efficiency of 77.7%.
learn more about Electrolytic cells here: https://brainly.com/question/28303387
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