Respuesta :
Balanced formation equation at standard conditions [tex]\frac{1}{2}[/tex] H₂ (g) + [tex]\frac{1}{2}[/tex] N₂ (g) + [tex]\frac{3}{2}[/tex] O₂ (g) → HNO₃ (l) [ΔH° (H₂ (g)) = 0 and ΔH° (N₂ (g)) = 0 and ΔH° (O₂ (g)) = 0].
What is Chemical Reaction ?
A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form a other new substances.
The chemical reaction for HNO₃ is
H₂ (g) + N₂ (g) + O₂ (g) → HNO₃ (l)
Reactant Side Product Side
H = 2 H = 1
N = 2 N = 1
O= 2 O = 3
In the reactant side there are 2 H atoms and in the product side 1H atoms. So multiply by [tex]\frac{1}{2}[/tex] in the reactant side to balance H atoms.
[tex]\frac{1}{2}[/tex] H₂ (g) + N₂ (g) + O₂ (g) → HNO₃ (l)
Reactant Side Product Side
H = 1 H = 1
N = 2 N = 1
O= 2 O = 3
In the reactant side there are 2 N atoms and in the product side 1 N atoms. So multiply by [tex]\frac{1}{2}[/tex] in the reactant side to balance N atoms.
[tex]\frac{1}{2}[/tex] H₂ (g) + [tex]\frac{1}{2}[/tex] N₂ (g) + O₂ (g) → HNO₃ (l)
Reactant Side Product Side
H = 1 H = 1
N = 1 N = 1
O= 2 O = 3
In the reactant side there are 2 O atoms and in the product side 3 O atoms. So multiply by [tex]\frac{3}{2}[/tex] in the reactant side to balance O atoms.
[tex]\frac{1}{2}[/tex] H₂ (g) + [tex]\frac{1}{2}[/tex] N₂ (g) + [tex]\frac{3}{2}[/tex] O₂ (g) → HNO₃ (l)
Reactant Side Product Side
H = 1 H = 1
N = 1 N = 1
O= 3 O = 3
Now the above equation is balanced.
Now, write the balanced formation equation at standard conditions
[tex]\frac{1}{2}[/tex] H₂ (g) + [tex]\frac{1}{2}[/tex] N₂ (g) + [tex]\frac{3}{2}[/tex] O₂ (g) → HNO₃ (l) [ΔH° (H₂ (g)) = 0 and ΔH° (N₂ (g)) = 0 and ΔH° (O₂ (g)) = 0]
Thus from the above conclusion we can say that Balanced formation equation at standard conditions [tex]\frac{1}{2}[/tex] H₂ (g) + [tex]\frac{1}{2}[/tex] N₂ (g) + [tex]\frac{3}{2}[/tex] O₂ (g) → HNO₃ (l) [ΔH° (H₂ (g)) = 0 and ΔH° (N₂ (g)) = 0 and ΔH° (O₂ (g)) = 0]
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