Iodine is the only halogen that occurs in a positive oxidation state, in NaIO₃ impurities within Chile saltpeter, NaNO₃.(c) If 0.78 mol % of an NaNO₃ deposit is NaIO, how much I₂ (in g) can be obtained from 1.000 ton (2000. lb) of the deposit?

The balanced equation representing the formation of I2 from I03 and HSO 3is as follows: 2I03 (aq) + 5HSO3(aq) =;3HSO4 (aq) + 2SO4 (aq) + H₂O(l) + I2 (s)

According to the equation 2 moles of IO3 produces 1 mole of I2. Molar mass of mass of iodine (i2) is 253.8 g/mol'

Relationships used are as follows: 2 mol IO3 = 1 mol I₂1 mol I2= 253.8 g I2, Number of moles of NaIO, is 83.23 mol NaIO3.

Multiply the number of moles of NaIO3, with the conversion factors obtained from the mole ratio of the stoichiometric equation and the molar mass of I2 to calculate the amount of I₂ produced.

(83.23 ×1×1×253.8)/1×2×1 = 1.056×10^4 g

Therefore, amount of iodine obtained is 1.056×10^4 g

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