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Like heavy water (D₂O), so-called "semi-heavy water" (HDO) undergoes H/D exchange. The molecular scenes depict an initial mixture of HDO and H₂ reaching equlibrium.(b) Is the value of K greater or less than 1?

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cenonjeric3

The Value of K is less than 1. K is equal to 0.44.

The connection between the products and reactants of a reaction when it is in equilibrium with regard to a certain unit is expressed by the equilibrium constant, K.

The concentrations of each component participating in a single reaction are measured after it has reached equilibrium in order to determine the numerical value of the equilibrium constant.

Calculations are made to determine the ratio of reactant concentrations to product concentrations. Since the concentrations are measured at equilibrium, the equilibrium constant is unaffected by the beginning concentrations for any particular reaction.

  • The balanced chemical equation for the reaction is

        HDO+H2 HD + H₂O

  • At equilibrium, the number of moles of reactants is greater than products. This is a reactant-favored reaction so the equilibrium constant K must be less than one.
  • The equilibrium constant is the ratio of product of concentration of products to that of concentration reactants with coefficients raised to their power. Considering each molecule depicted is 0.1M.

        K = ([H2O][HD])/([HDO][H2])

        K = ([0.2][0.2])/([0.3][0.3])

        K = 0.44

To know more about solving for equilibrium constant, click this:

https://brainly.com/question/10038290

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