The molarity of KI diluted in water is 0.01 M.
Molarity is the number of moles of solute present in volume of solution. The volume of solution is taken in liters.
Now looking at the values given in question -
Initial volume(V₁) - 8.25 mL
Initial molarity(M₁) - 2.00x10⁻² M
Final volume(V₂) - 12.0 ml
To calculate final molarity, we will use the following relation between given initial and final quantities -
M₁V₁ = M₂V₂
Keep the values in equation to find the final molarity of KI diluted with water.
M₂ = M₁V₁/V₂
M₂ = [tex]\frac{8.25*2*10^{-2} }{12.0}[/tex]
Performing multiplication and division to find the molarity
Molarity = 0.01 M
Thus, the molarity of KI diluted to 12.0 mL with water is 0.01 M.
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