The order of decreasing energy is ultraviolet rays, infrared rays, and microwaves.
The quantity of an event's occurrences is referred to as its frequency. Frequency in a wave function is the number of times a waveform passes past a spot. Hertz is the unit of frequency used in the International System of Units.
Particles with energy but no mass are called photons. The formula for calculating photon energy is frequency times Planck's constant h (6.63 10-34 J/s). Therefore, the relationship between frequency and photon energy is straightforward.
Waves with a higher frequency will be more energetic. Waves with a lower frequency will be less energetic.
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Complete question is:
Rank the following photons in terms of decreasing energy:
(a) IR (v = 6.5 x 10¹³ s⁻¹)
(b) microwave (v = 9.8 x 10¹¹ s⁻¹)
(c) UV (v = 8.0 x 10¹⁵ s⁻¹)
