Calculate the molarity of each aqueous solution:
(b) 38.5 mL of 1.2 M HNO₃ diluted to 0.130 L with water

Respuesta :

The molarity of given aqueous solution is 1200 M.

Initial volume = 38.5 ml

Initial molarity = 1.2 M

Final volume = 0.130 L

Firstly, converting milliliters to liters.

As we know, 1000 milliliters = 1 liters

So, 38.5 milliliters = [tex]\frac{1*38.5}{1000}[/tex]

Performing division to find the volume in liters

38.5 milliliters = 0.0385 liters

Now, calculating molarity of given aqueous solution using the relation -

M₁V₁ = M₂V₂

Keep the values in formula to find final molarity or M₂

M₂ = M₁V₁/V₂

M₂ = [tex]\frac{1.2*38.5}{0.0385}[/tex]

Performing multiplication and division to find molarity of aqueous solution

Molarity = 1200 M

Hence, the molarity of the given aqueous solution is 1200 M.

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