The order of decreasing wavelength is b >c >a >d
The formula for wavelength in terms of the rydberg constant
1/ λ = Rh * (1/n₁² - 1/n₂² )
where Rh = Rydberg constant
n = quantum numbers
For n = 2 to n = [infinity]
1/ λ = Rh * (1/2² - 1/∞² )
λ = 4 / Rh
For n = 4 to n= 20
1/ λ = Rh * (1/4² - 1/20² )
λ = 16.7 / Rh
For n = 3 to n = 10
1/ λ = Rh * (1/3² - 1/10² )
λ = 9.9 / Rh
For n = 2 to n = 1
1/ λ = Rh * (1/2² - 1/1² )
λ = 1.33 / Rh
Hence, the order of decreasing wavelength is
b >c >a >d
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Complete question:
Arrange the following H atom electron transitions in order of decreasing wavelength of the photon absorbed or emitted:
(a) n = 2 to n = [infinity]
(b) n = 4 to n = 20
(c) n = 3 to n = 10
(d) n = 2 to n = 1
