Respuesta :
The concentration of [tex]$Ca^{2+}[/tex] and [tex]$Mg^{2+}[/tex] ions are 2.797 ppm and 0.212 ppm.
How to find the mass of the solution?
Density of substances
= Mass of substances / Volume of substances
Volume of gold = 100 L = 100000 mL (Conversion factor: 1 L = 1000 mL)
Density of gold = 1.001 g/mL
substitute the values in the above equation, we get:
1.001 g/mL = Mass of substances / 100000 mL
Mass of substances [tex]$= 1.001 * 10^{5} $g[/tex]
To estimate the concentration in ppm (by mass), we use the equation:
ppm = (Mass of solute /Mass of substances) [tex]$* 10^6[/tex]
Calculating the concentration of calcium ions:
Mass of [tex]$Ca^{2+}[/tex] ions = 0.280 g
Putting values in the above equation, we get:
ppm [tex]$(Ca^{2+}) = \frac{0.280g}{1.001*10^5}*10^6[/tex]
= 2.797 ppm
Calculating the concentration of magnesium ions:
Mass of [tex]$Mg^{2+}[/tex] ions = 0.0220 g
Putting values in the above equation, we get:
ppm[tex]$ (Mg^{2+}) = \frac{0.0220 g}{1.001*10^5}*10^6[/tex]
= 0.212 ppm
Therefore, the concentration of [tex]$Ca^{2+}[/tex] and [tex]$Mg^{2+}[/tex] ions are 2.797 ppm and 0.212 ppm respectively.
To learn more about the mass of the solution refer to:
https://brainly.com/question/24658038
#SPJ4
