The answer is 3.3×10∧ −5 mol moles of solute particles are present in 1 mL of 0.08 M pyridine
moles of solute particles are present in 1 mL of 0.08 M pyridine (C₅H₅N)
n=Molarity×Volume
n=0.033M×1mL
n=0.033 Lmol ×10 −3L[∴M=mol/Land1mL=10 −3 L]
n=3.3×10 ∧-5 mol
Pyridine is a versatile solvent since it is polar but aprotic. It is completely miscible with a wide range of solvents, including hexane and water. Pyridines create stable salts with strong acids, such as deuterated pyridine (pyridine-d5). Pyridine is frequently employed as a basic solvent and to neutralise acid produced in a process.
Pyridine dissolves entirely in water, whereas benzene is just somewhat soluble. Benzene, like other hydrocarbons, is acid-base neutral, whereas pyridine is a weak base due to its nitrogen atom.
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