Respuesta :
0.008161 gms is the minimum mass of glycerol is required to prevent the solution from freezing at - 15°C.
A liquid's freezing point is the temperature at which it turns into a solid. Similar to the melting point, the freezing point typically rises with increasing pressure.
Given;
We require a depression in the freezing point of -15.0°c in order to have a freezing point of -15.0°c. We are aware that a colligative property of depression in freezing point depends on molality as
Depression in freezing point = Kf x molality
where, Kf = 1.86 °C/m
Molality = moles of solute/moles of solvent
15 = 1.86 °C/m X Molality
Molality = 8.065
Molality = Moles of glycerol/mass of water
Moles of glycerol = 8.065 X 11 X 10⁻⁶ = 88.715 X 10⁻⁶
Moles = mass / molar mass
Mass = moles X molar mass = 88.715 X 10⁻⁶X 92 = 0.008161 gms
0.008161 gms is the minimum mass required.
Learn more about the Freezing point with the help of the given link:
https://brainly.com/question/3121416
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