A rectangular field is ten times as long as it is wide. If the perimeter of the field is 1320 feet, what are the dimensions of the field?
A) Write an equation you can use to answer the given question. Let w be the width of the field.
The equation is _
(Make sure you use the correct variable.)
B) Use your equation to find the dimensions of the field.
The width of the field is _ feet.
The length of the field is ___ feet.

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swapnalimalwadeVT swapnalimalwadeVT · Answer 1 · 2022-08-26T22:22:19+02:00

The equation is P = 2 ( L + W )

The width of the field is 60 feet.

The length of the field is 600 feet.

Given,

A rectangular field is ten times as long as it is wide.

The perimeter of the field is 1320 feet.

Area of rectangle = Length x wide.

Perimeter = 2 ( Length + width )

Let the length of the rectangle be L

Width = W

L = 10W

Perimeter + 2 ( L + W )

1320 = 2 ( 10W + W )

Divide it by 2 into both sides.

1320/2 = 2/2 x 11W

660 = 11W

Divide both sides by 11.

660/11 = 11/11 W

60 = W

W = 60 feet

L = 10W = 10 X 60 = 600 feet

L = 600 feet

Thus,

The equation is P = 2 ( L + W )

The width of the field is 60 feet.

The length of the field is 600 feet.

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